I don't really know where to start in solving this functions, any help would be much appriciated.
Solve for x. log2(3x – 8) ≥ 6
Solve for x. log556x+1 = 13
As you learned when graphing log functions, the height of the line increases as the input value increases. So I believe we can convert the above to the following:
. . . . .$\displaystyle \log_2(3x\, -\, 8)\, \ge \,\log_2(2^6)$
...and then equate the arguments:
. . . . .$\displaystyle 3x\, -\, 8\, \ge\, 2^6$
Solve the linear equation.
I will guess that the "556" is the base, and that the "1" is outside the log. Then solve by subtracting the 1 to the other side. Then raise each side as a power on 556:
. . . . .$\displaystyle 556^{\log_{556}(x)}\, =\, 556^{12}$
Simplify the left-hand side to get your answer.
I wouldn't bother plugging that into your calculator, though...