I don't really know where to start in solving this functions, any help would be much appriciated.

Solve for x. log2(3x – 8) ≥ 6

Solve for x. log556x+1 = 13

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- Mar 25th 2009, 02:03 PM14041471Help needed with "Exponential and Logarithm Functions"
I don't really know where to start in solving this functions, any help would be much appriciated.

Solve for x. log2(3x – 8) ≥ 6

Solve for x. log556x+1 = 13 - Mar 25th 2009, 02:56 PMstapel
As you learned when

**graphing log functions**, the height of the line increases as the input value increases. So I believe we can convert the above to the following:

. . . . .$\displaystyle \log_2(3x\, -\, 8)\, \ge \,\log_2(2^6)$

...and then equate the arguments:

. . . . .$\displaystyle 3x\, -\, 8\, \ge\, 2^6$

Solve the linear equation.

I will guess that the "556" is the base, and that the "1" is outside the log. Then**solve**by subtracting the 1 to the other side. Then raise each side as a power on 556:

. . . . .$\displaystyle 556^{\log_{556}(x)}\, =\, 556^{12}$

Simplify the left-hand side to get your answer.

I wouldn't bother plugging that into your calculator, though... (Surprised)