Can anyone help me solve these functions as I don't really know where to start with them. Thanks. log264 = log2(1/16) =
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Originally Posted by 14041471 Can anyone help me solve these functions as I don't really know where to start with them. Thanks. log264 = log2(1/16) = if $\displaystyle 2^6 = 64$ , then $\displaystyle \log_2(64)$ = ? following that same idea ... $\displaystyle 2^{-4} = \frac{1}{16}$
Logarithm can be defined as the inverse to the exponential function: $\displaystyle log_b(b^x)= x$. $\displaystyle 64= 2^6$ and $\displaystyle 1/16= 2^{-4}$.
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