Can anyone help me solve these functions as I don't really know where to start with them. Thanks.

log264 =

log2(1/16) =

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- Mar 25th 2009, 02:00 PM14041471Exponential and Logarithm Functions
**Can anyone help me solve these functions as I don't really know where to start with them. Thanks.**

log264 =

log2(1/16) = - Mar 25th 2009, 02:35 PMskeeter
- Mar 25th 2009, 04:28 PMHallsofIvy
Logarithm can be defined as the inverse to the exponential function:

$\displaystyle log_b(b^x)= x$.

$\displaystyle 64= 2^6$ and $\displaystyle 1/16= 2^{-4}$.