am I in the right track??

$\displaystyle 9\ge\frac{8-x}{4}>0$

$\displaystyle 9-2\ge\frac{-x}{4}>-2$

$\displaystyle 7(4)\ge-x>2(4)$

$\displaystyle 28\ge-x>8$

i am confused when changing -x to x

$\displaystyle 28\le x<-8$

is this correct??

another example

-x>-8

x<-8

thanks I'm confused