I need to find the value of x and y for the following equation:

$\displaystyle a^x * \frac {b^3} {b^x} * \frac {b^y} {(a^y * a^1)^2} = ab^6$

In order to find them, I need simultaneous equations but I just don't know how to get the simultaneous equations. Where can I get the second equation? Or is there any other way?

This is what I got so far(which may makes no sense):

Tried from numerators and denominators:

$\displaystyle x-2y+2=6$

$\displaystyle y-3-x=1$

Solved using substitution method:

$\displaystyle x=-12$

$\displaystyle y=-8$

Second attempt:

$\displaystyle x-2y+2=6$

$\displaystyle y-3-x=6$

Solved:

$\displaystyle x=-22$

$\displaystyle y=-13$

But both answers are wrong.

Please help.

Thanks.

Original equation here.