1. ## Help required

A travel agency gives following discounts to their customers as follows:-
0-6 days in advance - 0%

A persons pays $1050 for his ticket.Had he purchased the ticket 1 day later, he would have paid$210 more.How many days before did he purchase the ticket?

Can someone help me solve this problem?

2. Hi

You know that one day after he would not have paid the same price
Therefore he bought his ticket or 7 days or 14 days before

If it is 7 days before then he paid with a 10% decrease (he paid 0.9 time the normal price)
Therefore 0.9 p = 1050 => p = 1050/0.9 = 1166.67
The day after he would have paid the normal price p (because no reduction) which is 1166.67
But you know that he would have paid 210 more than 1050 = 1260
And 1166.67 is not equal to 1260
Therefore the hypothesis is wrong

If it is 14 days before ... your turn !

3. ## Percentages

Hello shanram74
Originally Posted by shanram74
A travel agency gives following discounts to their customers as follows:-
0-6 days in advance - 0%
A persons pays $1050 for his ticket.Had he purchased the ticket 1 day later, he would have paid$210 more.How many days before did he purchase the ticket?
If you get a 10% discount, you pay only 90% of the full price. This means that if you pay $$\displaystyle x, the full price is  \displaystyle \frac{100}{90}x. So could 1050 be 90% of the full price? No, because \displaystyle \frac{100}{90}\times 1050 gives an inexact decimal answer. (Try it and see!) On the other hand, if you get a 25% discount, you pay only 75% of the full price. So this time, if you pay$$\displaystyle x$, the full price is$ $\displaystyle \frac{100}{75}x$. How does this work with $1050? Well,$\displaystyle \frac{100}{75}\times 1050 = 1400$. This is better! So it looks as if the full price is$1400, and he's just managed to get a 25% discount. If he'd been a day later, he'd only have got a 10% discount...