If I can't factor a quadratic equation what will I do??

I don't know the latex for this.. thanks. I tried extracting the roots but it turned out as square root of a negative number?? Am I in the right track?

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- Mar 23rd 2009, 06:15 AM #1

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## [SOLVED] help

If I can't factor a quadratic equation what will I do??

I don't know the latex for this.. thanks. I tried extracting the roots but it turned out as square root of a negative number?? Am I in the right track?

- Mar 23rd 2009, 06:30 AM #2

- Mar 23rd 2009, 06:32 AM #3

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- Mar 23rd 2009, 06:44 AM #4

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This means theres no intersection with the x-axis. if you simply need to sketch the graph find the turning point of the quadratic should give you the X-coordinate of the turning point. Put that X-coordinate value into the non-differentiated equation and you'll get your Y-coordinate of the turning point

- Mar 23rd 2009, 06:49 AM #5

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- Mar 23rd 2009, 06:50 AM #6

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x = -1 is the x-coordinate of the Turning point, plug into the original equation for the Y-value of this Turning point

= 6

Coordinates of Turning point (-1,6) I'm guessing this is a minimum

i swear to god my computer pasted what i wrote twice. What in gods name happened there lol

- Mar 23rd 2009, 06:59 AM #7

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**Graph the quadratic**. Look at the picture. Look at the inequality.

You are asked to find the x-values for which the quadratic is at or above the x-axis. What does the picture show you?

- Mar 23rd 2009, 07:06 AM #8

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- Mar 23rd 2009, 07:31 AM #9

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If the various worked examples in the lesson (provided in the link) were not sufficiently helpful, then try studying a few more

**online lessons**. (I'm assuming you understand the x,y-plane and how to graph linear equations.)

Once you've learned how to do the graph, draw the picture.

- Mar 23rd 2009, 07:46 AM #10
A simple answer to your question is

-Roots are not real as square root of negative is not real

-Meaning graph never touches x axis , or in other words the quadratic function never has zero value

-This means that the quadratic is either always positive or always negative

(since to change from +ve to -ve you need to cross 0 )

**Result:**

Value of equation for all x is either always positive or always negative

----------------------------

**Application**:

Put x = any number , lets take it as 2

15>0, as derived earlier for all values of x this is equality holds that

thus answer is every real x

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No real need to draw a graph or learning it for answering this

- Mar 23rd 2009, 08:07 AM #11

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- Mar 23rd 2009, 08:10 AM #12

- Mar 23rd 2009, 08:13 AM #13

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- Mar 23rd 2009, 08:14 AM #14

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