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Math Help - Help with bouncing ball

  1. #1
    Asnera
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    Wink Help with bouncing ball

    Hi, anyone out there, my problem is pure logic that I obviously don't have at the mo.........

    A ball bounces everytime at 2/5 of the height of its bounce. If we let it fall 75 cm, calculate the height it reaches on the 2nd bounce.

    Please someone help me make sense of this
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  2. #2
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    earboth's Avatar
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    Quote Originally Posted by Asnera View Post
    A ball bounces everytime at 2/5 of the height of its bounce. If we let it fall 75 cm, calculate the height it reaches on the 2nd bounce.
    ...
    Hello, Asnera,

    The ball starts at a height of 75 cm. The height after the first bounce is (2/5)*75 cm = 30 cm. The height after the seconf bounce is (2/5)*30 cm = 12 cm.
    In general: Let n be the number of bounces and h the height with respect of n then:
    h(n)=75cm \cdot \left(\frac{2}{5}\right)^n

    EB
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