Help with bouncing ball
Hi, anyone out there, my problem is pure logic that I obviously don't have at the mo.........
A ball bounces everytime at 2/5 of the height of its bounce. If we let it fall 75 cm, calculate the height it reaches on the 2nd bounce.
Please someone help me make sense of this:eek:
Originally Posted by Asnera
The ball starts at a height of 75 cm. The height after the first bounce is (2/5)*75 cm = 30 cm. The height after the seconf bounce is (2/5)*30 cm = 12 cm.
In general: Let n be the number of bounces and h the height with respect of n then: