y+4=-1/2(x-3) I cant seem to get it to slope intercept form y=mx+b
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Originally Posted by steresopolis y+4=-1/2(x-3) I cant seem to get it to slope intercept form y=mx+b $\displaystyle y+4 = \frac{x-3}{-2} $ Subtract 4 from both sides $\displaystyle y = \frac{x-3}{-2} - 4 $ $\displaystyle y = \frac{x-3 + 8 }{-2}$ $\displaystyle y = \frac{x+5}{-2}$ $\displaystyle y = \frac{-x}{2} + \frac{-5}{2}$
Last edited by ADARSH; Mar 23rd 2009 at 12:45 AM. Reason: -ve sign
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