Given f(x)=8x^3, sketch the graph of g(x) in detail, where g(x)=f(x - 1)+1
Im unsure what to do!
do you sub in f(x) or...??
Since $\displaystyle f\!\left(x\right)=8x^3$, and $\displaystyle g\!\left(x\right)=f\!\left(x-1\right)+1$, this means that $\displaystyle g\!\left(x\right)=8\left(x-1\right)^3+1$.
All that you're doing with $\displaystyle f\!\left(x\right)$ is shifting it over one unit to the right (which is what $\displaystyle f\!\left(x-1\right)$ represents) and then shifting it up one unit (which is what $\displaystyle f\!\left(x-1\right)+1$ represents).
Does this make sense?