This a homework problem can someone explain how this $\displaystyle \frac{t-\frac{1}{t}}{2}$ equals this $\displaystyle \frac{t^2-1}{2t}$
Follow Math Help Forum on Facebook and Google+
make a common denominator for the numerator fraction x - (1/x) common denominator is x, so.. ((x^2 - 1) / x) all divided by 2, so.. (x^2 - 1 /2x)
Hello, sk8erboyla2004! Can someone explain how .$\displaystyle \frac{t-\frac{1}{t}}{2}$ .equals .$\displaystyle \frac{t^2-1}{2t}$ Multiply by $\displaystyle \frac{t}{t}\!:\quad\frac{t}{t}\cdot\frac{t - \frac{1}{t}}{2} \;=\;\frac{t^2-1}{2t}$
well sure if you wanna do it the eeeasy way
View Tag Cloud