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Math Help - Dividing variables with powers

  1. #1
    Newbie steresopolis's Avatar
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    Dividing variables with powers

    X3Y2
    X8Y-3 = y5X5



    why?, where does (x to the fifth power) come from?

    i thought its like 2+(-3)=-1 so it would be X -1 power


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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by steresopolis View Post
    X3Y2
    X8Y-3 = y5X5



    why?, where does (x to the fifth power) come from?

    i thought its like 2+(-3)=-1 so it would be X -1 power

    Both your question and answer dont match with each other complete it
    ---------------------------------------------
    These formulas will be used

    \frac{a^{b}}{a^{c}} = a^{b-c}

    <br />
a^{b}\times a^c = a^{b+c}
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  3. #3
    MHF Contributor
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    Talking

    I'm afraid I can't figure out what you mean...? (The apparent meaning of your posted expression cannot lead to the apparent meaning of the posted "answer", so something is wrong.)

    Please use LaTeX formatting, or (which is simpler) standard web-safe formatting to clarify your meaning.

    Thank you!

    P.S. If you're needing a review of exponent rules, including how to work with negative powers, try here.
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  4. #4
    Senior Member Pinkk's Avatar
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    x^{3-8}y^{2+3}=x^{-5}y^{5}=\frac{y^{5}}{x^{5}}=(\frac{y}{x})^{5}
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