Math Help - Dividing variables with powers

1. Dividing variables with powers

X3Y2
X8Y-3 = y5X5

why?, where does (x to the fifth power) come from?

i thought its like 2+(-3)=-1 so it would be X -1 power

2. Originally Posted by steresopolis
X3Y2
X8Y-3 = y5X5

why?, where does (x to the fifth power) come from?

i thought its like 2+(-3)=-1 so it would be X -1 power

Both your question and answer dont match with each other complete it
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These formulas will be used

$\frac{a^{b}}{a^{c}} = a^{b-c}$

$
a^{b}\times a^c = a^{b+c}$

3. I'm afraid I can't figure out what you mean...? (The apparent meaning of your posted expression cannot lead to the apparent meaning of the posted "answer", so something is wrong.)

Please use LaTeX formatting, or (which is simpler) standard web-safe formatting to clarify your meaning.

Thank you!

P.S. If you're needing a review of exponent rules, including how to work with negative powers, try here.

4. $x^{3-8}y^{2+3}=x^{-5}y^{5}=\frac{y^{5}}{x^{5}}=(\frac{y}{x})^{5}$