How about solving this:

$\displaystyle 6/5+3/(w-3)=9/[5(w-3)]$

LCD= 5(w-3)

$\displaystyle (6/5)(5)(w-3)+5(w-3)[3/(w-3)]=9/[5(w-3)](5)(w-3)$

$\displaystyle 6w-18+5w-15(3/(w-3)=9/[5(w-3)](5)(w-3)$

5w-15(3/(w-3)=9/[5(w-3)](5)(w-3) that's the part I'm having trouble with..