How about solving this:
$\displaystyle 6/5+3/(w-3)=9/[5(w-3)]$
LCD= 5(w-3)
$\displaystyle (6/5)(5)(w-3)+5(w-3)[3/(w-3)]=9/[5(w-3)](5)(w-3)$
$\displaystyle 6w-18+5w-15(3/(w-3)=9/[5(w-3)](5)(w-3)$
5w-15(3/(w-3)=9/[5(w-3)](5)(w-3) that's the part I'm having trouble with..