2x^2 + 51x - 81 = 0p.s. I know how to factor, but not something like 2x^2+51x-81=0
(2x - 3)(x + 27)
log(base3)x + log(base3)(2x+51) = 4
a) thank you for helping, I am a new member and love the looks of this site.
b) i am not asking you to do this, maybe just some help I am stuck
c) its not really homework, i am studying for a test on monday and just cant understand this
1) I know the rules of logs and this is where i get stuck:
log(base3)(2x+51)(x)=4
log(base3)2x^2+51x=4
2x^2+51x=3^4 --->2x^2+51x=81
? now do i divide both sides by 2? or should I have done that before i got rid of log(base3)?
p.s. I know how to factor, but not something like 2x^2+51x-81=0
Any help would be amazing, even a little input if your not sure to get me thinking. Thanks!
Before your test, you might want to review some online lessons to refresh your memory regarding factoring quadratics.
Good luck on the test!