This is not correct (*),where do I go from here?
is this also correct ?
(*) if a and b are negative, there will be some problems for defining the logarithm...
Anyway, here is what I did :
- if a,b=0, then the equality is always true, for any x and y. So it is true to say that x+y=1
- if a,b=1, same as above
- if a,b 0 or 1 :
this is true iff , that is to say
similarly for b, we get
- if x+y-1=0, then y=1 and we have x+y=1
- if y=0, then there is a problem here...
if x+y-1=0, everything is ok.
I wonder if you stated all the conditions over a,b,x and y...