# Thread: Help with an equation

1. ## Help with an equation

[j/2] - [j-3/4] = 9/4

2. do u mean $\frac{j}{2} - \frac{j-3}{4}$

3. Originally Posted by ambergarrett055
[j/2] - [j-3/4] = 9/4
$\frac{j}{2} - \left(j - \frac{3}{4}\right) = \frac{9}{4}$

or

$\frac{j}{2} - \frac{j-3}{4} = \frac{9}{4}$

?

4. The second one....j-3 over 4. Sorry. I'm new to this.

5. $\frac{j}{2} - \frac{j-3}{4} = \frac{9}{4}$

multiply every term by 4 to clear the fractions ...

$2j - (j - 3) = 9$

can you finish from here?

6. Yep. Thanks..I just wanted to make sureI multiplied both sides by four to get rid of the fractions. Thanks!

7. Originally Posted by ambergarrett055
Yep. Thanks..I just wanted to make sureI multiplied both sides by four to get rid of the fractions. Thanks!
next time, show all your work.

8. I have another equation, too. Do I multiply both sides by 10?

[9t + 1] / 5 = [t+8] /10 + [t-6] /10

9. Originally Posted by ambergarrett055
I have another equation, too. Do I multiply both sides by 10?

[9t + 1] / 5 = [t+8] /10 + [t-6] /10
yes

10. I keep getting t=0 but when I check it it doesn't work out. I'll just keep trying. Thanks!

11. Originally Posted by ambergarrett055
[9t + 1] / 5 = [t+8] /10 + [t-6] /10
$2(9t+1) = (t+8) + (t-6)$

$18t + 2 = 2t + 2$

$18t = 2t$

$t = 0$

check ...

$\frac{1}{5} = \frac{8}{10} - \frac{6}{10}$

$\frac{1}{5} = \frac{1}{5}$

checks good.