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Math Help - Help with an equation

  1. #1
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    Help with an equation

    [j/2] - [j-3/4] = 9/4
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  2. #2
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    do u mean  \frac{j}{2} - \frac{j-3}{4}
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  3. #3
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    Quote Originally Posted by ambergarrett055 View Post
    [j/2] - [j-3/4] = 9/4
    \frac{j}{2} - \left(j - \frac{3}{4}\right) = \frac{9}{4}

    or

    \frac{j}{2} - \frac{j-3}{4} = \frac{9}{4}

    ?
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  4. #4
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    The second one....j-3 over 4. Sorry. I'm new to this.
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  5. #5
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    \frac{j}{2} - \frac{j-3}{4} = \frac{9}{4}

    multiply every term by 4 to clear the fractions ...

    2j - (j - 3) = 9

    can you finish from here?
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  6. #6
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    Yep. Thanks..I just wanted to make sureI multiplied both sides by four to get rid of the fractions. Thanks!
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  7. #7
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    Quote Originally Posted by ambergarrett055 View Post
    Yep. Thanks..I just wanted to make sureI multiplied both sides by four to get rid of the fractions. Thanks!
    next time, show all your work.
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  8. #8
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    I have another equation, too. Do I multiply both sides by 10?


    [9t + 1] / 5 = [t+8] /10 + [t-6] /10
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  9. #9
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    Quote Originally Posted by ambergarrett055 View Post
    I have another equation, too. Do I multiply both sides by 10?


    [9t + 1] / 5 = [t+8] /10 + [t-6] /10
    yes
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  10. #10
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    I keep getting t=0 but when I check it it doesn't work out. I'll just keep trying. Thanks!
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  11. #11
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    Quote Originally Posted by ambergarrett055 View Post
    [9t + 1] / 5 = [t+8] /10 + [t-6] /10
    2(9t+1) = (t+8) + (t-6)

    18t + 2 = 2t + 2

    18t = 2t

    t = 0

    check ...

    \frac{1}{5} = \frac{8}{10} - \frac{6}{10}

    \frac{1}{5} = \frac{1}{5}

    checks good.
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