Here I go again Simplify: $\displaystyle \sqrt[n] {\frac{2^{28} + 2^{30}}{10}} $
Last edited by mr fantastic; Mar 18th 2009 at 05:25 AM. Reason: Fixed the latex in this post - again .... And provided clarity
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Originally Posted by _icebox Here I go again $\displaystyle \sqrt[n] {2^28 + 2^30} / {10} $ $\displaystyle \dfrac{\sqrt[n] {2^{28} + 2^{30}}}{ {10}} = \dfrac{2^{\frac{28}{n}}(1+2^2)^{\frac1n}}{2^1 \cdot 5^1} = 2^{\frac{28-n}n} \cdot 5^{\frac{1-n}n} $
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