Simplifying an expression with 2's raised to powers

Printable View

March 18th 2009, 04:39 AM
_icebox

Simplifying an expression with 2's raised to powers

Hey people!

Can you help, please?!

$ \frac{2^n+^4 - 2.2^n} {2.2^n+^3} $

It's easy?!

I just can't transform those stuffs in numbers (Headbang) !!!
March 18th 2009, 05:13 AM
ADARSH

Quote:

Originally Posted by _icebox

Hey people!

Can you help, please?!

$ \frac{2^n+^4 - 2.2^n} {2.2^n+^3} $

It's easy?!

I just can't transform those stuffs in numbers (Headbang) !!!

If this is your question

$ \frac{2^{n+4} - 2\times2^n} {2.2^{n+3}} $

$ a^{x} \times a^{y} = a^{x+y}$

$ =\frac{2^{n+4} - 2^{n+1}} {2^{n+4}} $

$ =\frac{2^{n+4} - 2^{n+1}} {2^{n+4}} $

Divide numerator and denominator by $2^{n+1}$

$ =\frac{2^{3} - 1} {2^{3}} $

$ =\frac{8 - 1} {8} $

$ =\frac{7} {8} $
March 18th 2009, 05:22 AM
masters

Quote:

Originally Posted by ADARSH

If this is your question

$ \frac{2^{n+4} - 2\times2^n} {2.2^{n+3}} $

$ a^{x} \times a^{y} = a^{x+y}$

$ =\frac{2^{n+4} - 2^{n+1}} {2^{n+4}} $

$ =\frac{2^{n+4} - 2^{n+1}} {2^{n+4}} $

Divide numerator and denominator by $2^{n+1}$

$ =\frac{2^{3} - 1} {2^{3}} $

$ =\frac{8 - 1} {8} $

$ =\frac{7} {8} $

I'm impressed that you could interpret $2.2^n$ as $2 \cdot 2^n$ .

I was having a tough time fooling around with the decimal.
March 18th 2009, 05:25 AM
ADARSH

Quote:

Originally Posted by masters

I'm impressed that you could interpret $2.2^n$ as $2 \cdot 2^n$ .

I was having a tough time fooling around with the decimal.

The time I saw that + sign jumping up and down , I knew interpretation is the keyword :p ..(Giggle)
March 18th 2009, 05:27 AM
_icebox

Yes! That's it!!! (Clapping)

I've some problems with the Latex... I don't know exacly how to use that hauhauhaha

But that's exacly what I was looking for =D
I stopped when it was necessary to divide numerator and denominator =P

thank you, ADARSH!