Hey people!

Can you help, please?!

$\displaystyle

\frac{2^n+^4 - 2.2^n} {2.2^n+^3}

$

It's easy?!

I just can't transform those stuffs in numbers (Headbang) !!!

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- Mar 18th 2009, 04:39 AM_iceboxSimplifying an expression with 2's raised to powers
Hey people!

Can you help, please?!

$\displaystyle

\frac{2^n+^4 - 2.2^n} {2.2^n+^3}

$

It's easy?!

I just can't transform those stuffs in numbers (Headbang) !!! - Mar 18th 2009, 05:13 AMADARSH
If this is your question

$\displaystyle

\frac{2^{n+4} - 2\times2^n} {2.2^{n+3}}

$

$\displaystyle

a^{x} \times a^{y} = a^{x+y}$

$\displaystyle

=\frac{2^{n+4} - 2^{n+1}} {2^{n+4}}

$

$\displaystyle

=\frac{2^{n+4} - 2^{n+1}} {2^{n+4}}

$

Divide numerator and denominator by $\displaystyle 2^{n+1} $

$\displaystyle

=\frac{2^{3} - 1} {2^{3}}

$

$\displaystyle

=\frac{8 - 1} {8}

$

$\displaystyle

=\frac{7} {8}

$ - Mar 18th 2009, 05:22 AMmasters
- Mar 18th 2009, 05:25 AMADARSH
- Mar 18th 2009, 05:27 AM_icebox
Yes! That's it!!! (Clapping)

I've some problems with the Latex... I don't know exacly how to use that hauhauhaha

But that's exacly what I was looking for =D

I stopped when it was necessary to divide numerator and denominator =P

thank you, ADARSH!