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Math Help - Simplifying an expression with 2's raised to powers

  1. #1
    Newbie _icebox's Avatar
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    Thumbs up Simplifying an expression with 2's raised to powers

    Hey people!

    Can you help, please?!

    <br /> <br />
\frac{2^n+^4 - 2.2^n} {2.2^n+^3}<br /> <br />

    It's easy?!

    I just can't transform those stuffs in numbers !!!
    Last edited by _icebox; March 18th 2009 at 05:02 AM. Reason: ((( Why the title has changed?! )))
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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by _icebox View Post
    Hey people!

    Can you help, please?!

    <br /> <br />
\frac{2^n+^4 - 2.2^n} {2.2^n+^3}<br /> <br />

    It's easy?!

    I just can't transform those stuffs in numbers !!!
    If this is your question

    <br /> <br />
\frac{2^{n+4} - 2\times2^n} {2.2^{n+3}}<br /> <br />

    <br />
a^{x} \times a^{y} = a^{x+y}

    <br /> <br />
 =\frac{2^{n+4} - 2^{n+1}} {2^{n+4}}<br /> <br />

    <br /> <br />
  =\frac{2^{n+4} - 2^{n+1}} {2^{n+4}}<br /> <br />

    Divide numerator and denominator by 2^{n+1}

    <br /> <br />
   =\frac{2^{3} - 1} {2^{3}}<br /> <br />

    <br /> <br />
    =\frac{8 - 1} {8}<br /> <br />



    <br /> <br />
     =\frac{7} {8}<br /> <br />
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  3. #3
    A riddle wrapped in an enigma
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    Quote Originally Posted by ADARSH View Post
    If this is your question

    <br /> <br />
\frac{2^{n+4} - 2\times2^n} {2.2^{n+3}}<br /> <br />

    <br />
a^{x} \times a^{y} = a^{x+y}

    <br /> <br />
=\frac{2^{n+4} - 2^{n+1}} {2^{n+4}}<br /> <br />

    <br /> <br />
=\frac{2^{n+4} - 2^{n+1}} {2^{n+4}}<br /> <br />

    Divide numerator and denominator by 2^{n+1}

    <br /> <br />
=\frac{2^{3} - 1} {2^{3}}<br /> <br />

    <br /> <br />
=\frac{8 - 1} {8}<br /> <br />



    <br /> <br />
=\frac{7} {8}<br /> <br />
    I'm impressed that you could interpret 2.2^n as 2 \cdot 2^n.

    I was having a tough time fooling around with the decimal.
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  4. #4
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by masters View Post
    I'm impressed that you could interpret 2.2^n as 2 \cdot 2^n.

    I was having a tough time fooling around with the decimal.
    The time I saw that + sign jumping up and down , I knew interpretation is the keyword ..
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  5. #5
    Newbie _icebox's Avatar
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    Yes! That's it!!!

    I've some problems with the Latex... I don't know exacly how to use that hauhauhaha

    But that's exacly what I was looking for =D
    I stopped when it was necessary to divide numerator and denominator =P

    thank you, ADARSH!
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