2/3 = 5n-81/{([n-1]/4)^2 -10} What is n?

All help greatly appreciated (Happy)

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- March 18th 2009, 03:17 AMolliemanAlgerbra
2/3 = 5n-81/{([n-1]/4)^2 -10} What is n?

All help greatly appreciated (Happy) - March 18th 2009, 04:15 AMADARSH
- March 18th 2009, 04:21 AMstapel
Your

**formatting**is ambiguous; I*think*you mean the following:

. . . . .

If so, then a good first step in**solving this rational equation**is probably to multiply through, to get rid of the denominators:

. . . . .

. . . . .

. . . . .

. . . . .

Then collect all the terms on one side of the "equals" sign:

. . . . .

Then apply**the Quadratic Formula**to solve for "n". Remember to check your solutions in the*original*equation, making sure that they don't cause any "division by zero" problems. :D