Thread: Simple indices question..

Solve the equation 4^2x x 8^(x-1) = 32

Usually I solve these using logs and antilogs but here the question specifies that I cannot use that way as it's too basic.

I get the answer, x = 8/7 using logs/antilogs but I am not sure how to do it using a just the indices and surds rules.

Originally Posted by struck

Solve the equation 4^2x x 8^(x-1) = 32

Usually I solve these using logs and antilogs but here the question specifies that I cannot use that way as it's too basic.

I get the answer, x = 8/7 using logs/antilogs but I am not sure how to do it using a just the indices and surds rules.

4^2x x 8^(x-1) = 32

I think you mean










Thus
7x-3 = 5

x= 8/7

Originally Posted by struck

Solve the equation 4^2x x 8^(x-1) = 32

Usually I solve these using logs and antilogs but here the question specifies that I cannot use that way as it's too basic.

I get the answer, x = 8/7 using logs/antilogs but I am not sure how to do it using a just the indices and surds rules.