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Math Help - Factoring Special Products.

  1. #1
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    Factoring Special Products.

    These are start to get way to hard now.

    Need help on these.







    The answers all ready there are 'given.'

    I need help with these, I'm a Senior who is failing in Math. I wanna Grad on time.
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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by Kenlen83 View Post
    These are start to get way to hard now.

    Need help on these.







    The answers all ready there are 'given.'

    I need help with these, I'm a Senior who is failing in Math. I wanna Grad on time.
    Remember this formula

    (ax)^ 3 + (by)^3 = (ax+by)\times((ax)^2 + (by)^2 - axby)



    Example ;

    x^3 + 1/8

    = (x)^3 + (1/2)^3 = (x+1/2)(x^2 +1/4 -x/2)

    27 x^3 + 1

    = (3x)^3 + (1)^3 = (3x+1)(9x^2 + 1 - 3x)
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  3. #3
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    These are all sums or differences of cubes:

    . . . . . x^3\, +\, \frac{1}{8}\, =\, (x)^3\, +\, \left(\frac{1}{2}\right)^3

    . . . . . a^{3y}\, +\, 1\, =\, \left(a^y\right)^3\, +\, (1)^3

    . . . . . \frac{1}{8}x^3\, -\, \frac{1}{27}y^3\, =\, \left(\frac{1}{2}x\right)^3\, -\, \left(\frac{1}{3}y\right)^3

    To learn how to do the factorizations, try studying a lesson on special factoring formulas.

    Then memorize the two "cubes" formulas!!
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  4. #4
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    Hey, Thanks... Does that work with both? Can you give me a Example how Number 7 work with that?
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  5. #5
    A riddle wrapped in an enigma
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    Quote Originally Posted by Kenlen83 View Post
    Hey, Thanks... Does that work with both? Can you give me a Example how Number 7 work with that?
    Hi Kenlen83,

    a^{3y}+1=(a^y)^3+1^3=(a^y+1)(a^{2y}-a^y+1)
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  6. #6
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    Big Thanks for this.

    Thanks everyone, best math site i been on.
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