Hello, puzzledwithpolynomials!
Solve for
This can be written: .
We have: .
.
. . . .
.
Therefore: .
I'm not familiar with LaTex, so bear with my notation (I apologize in advance)...
Find the values of x and y for which...
[2y+5 = [x-1
y-2] = 3x]
is true.
My work thus far
2y+5=x-1; (0,-3)
y-2=x-1; (-2/3, 0)
...I just don't know what steps to take particularly.
If the previous reply's interpretation is correct, you have the following matrix equality:
. . . . .
It may be simpler, in this case, to use what you know about matrix equality to create regular equations:
. . . . .
. . . . .
Rearrange to get the variables on one side of the "equals" signs, and the constant terms on the other:
. . . . .
. . . . .
. . . . .
. . . . .
Multiply the first row by -3 and add down to get:
. . . . . ..
. . . . .
. . . . . . . . ..
Etc, etc.