Originally Posted by

**allywallyrus** i'm not sure which forum this belongs in, but this seemed like the closest fit. the question is asking me to solve for x and i'm kinda stuck

heres what i have:

2x^3+6x^2-x=3

so i brought the 3 over and found out -3 is a factor

f(-3)=2(-3^3)+6(-3^2)-(-3)-3

0=-54+54+3-3

but then when i divide the initial equation by x+3 it end up with a zero and then i dont really know where to go from there

ideas?

Hi allywallyrus,

First of all, **-3** is not a factor. **-3** is a zero (root) of $\displaystyle f(x)=2x^3+6x^2-x-3$

$\displaystyle x+3$ is a factor.

Using synthetic division, we can easily find the depressed polynomial in the 2nd degree.

Code:

-3 | 2 6 -1 -3
-6 0 3
-------------
2 0 -1 0

The depressed polynomial is $\displaystyle 2x^2-1=0$, which you can easily find the remaining 2 zeros.