2(2(2x-12)-12)-12=9
He's still the same man when he goes to another city. Plug the result of one city into the equation of the next city.
Hello everyone,
Could someone please help me with this double false position problem?
A buisness man doubled his money and he spent $12. He then left and doubled his money in another city and spent $12. He returned and doubled his money, and spent $12. At the end of the 3 trips and after the expenses he has $9 left. How much did he have at the begining?
I know the answer is 11.625
Do you see where I went wrong?
the algebraic way:
(2x-12)+(2x-12)+(2x-12)=9
6x=45
x=7.5
Double false position:
Guess $100
($100)2-12=188
($100)2-12=188
($100)2-12=188
________________
564
564-9=555
Guess #2 $50
(50)2-12=88
(50)2-12=88
(50)2-12=88
__________
264
264-9=255
100 555
50 255
cross multiply: (100)(255)=25500
(50)(555)=27750
Take the difference:
27750-25500=2250
2250/difference in error=
2250/555-255 =
7.5
Thank you very much