# Algebra word problem

• Mar 14th 2009, 02:18 PM
GriceldaM
Algebra word problem
i need help witht the following problem-

A merchant mixed 10 lb of cinnamon tea with 5 lb of spice tea. The 15-pound mixture cost

\$40. A second mixture included 12 lb of the cinnamon tea and 8 lb of the spice tea. The 20-
pound mixture cost \$54. Find the cost per pound of the cinnamon tea and of the spice tea.

thanks!
• Mar 14th 2009, 02:45 PM
e^(i*pi)
Quote:

Originally Posted by GriceldaM
i need help witht the following problem-

A merchant mixed 10 lb of cinnamon tea with 5 lb of spice tea. The 15-pound mixture cost

\$40. A second mixture included 12 lb of the cinnamon tea and 8 lb of the spice tea. The 20-
pound mixture cost \$54. Find the cost per pound of the cinnamon tea and of the spice tea.

thanks!

Let cinnamon tea be x and spice tea be y@

10x + 5y = 40 which simplifies to 2x+y=8

12x + 8y = 54 which simplifies to 6+4y = 27

which can then be solved easily enough enough
• Mar 14th 2009, 02:54 PM
GriceldaM
woohoo! thanks so much!