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  1. #1
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    Exclamation algebra word problem

    help please!

    A pharmacist has two vitamin-supplement powders. The first powder is 20% vitamin B1 and 10% vitamin B2. The second is 15% vitamin B1 and 20% vitamin B2. How many milligrams of each of the two powders should the pharmacist use to make a mixture that contains 130 mg of vitamin B1 and 80 mg of vitamin B2?

    any ideas on how to do this?
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  2. #2
    Member u2_wa's Avatar
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    Quote Originally Posted by GriceldaM View Post
    help please!

    A pharmacist has two vitamin-supplement powders. The first powder is 20% vitamin B1 and 10% vitamin B2. The second is 15% vitamin B1 and 20% vitamin B2. How many milligrams of each of the two powders should the pharmacist use to make a mixture that contains 130 mg of vitamin B1 and 80 mg of vitamin B2?

    any ideas on how to do this?
    Hello GriceldaM
    Let x & y be the quantity of first and second powder respectively.
    First powder =0.2x (vit B1), 0.1x (vit B2)
    second powder =0.15y (vit B1), 0.2y (vit B2)
    Vit B1: 0.2x+0.15y=130
    Vit B2: 0.1x+0.2y=80
    Solve to get the values of x & y.
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  3. #3
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by GriceldaM View Post
    help please!

    A pharmacist has two vitamin-supplement powders. The first powder is 20% vitamin B1 and 10% vitamin B2. The second is 15% vitamin B1 and 20% vitamin B2. How many milligrams of each of the two powders should the pharmacist use to make a mixture that contains 130 mg of vitamin B1 and 80 mg of vitamin B2?

    any ideas on how to do this?

    Lets say he took x milligrams of 1st and y mg of 2nd


    -------------------------------------
    So composition of 1st powder has

    Amount of B1 = \frac{20 \times x}{100} = \frac{x}{5}

    Amount of B2 = \frac{10 \times x}{100} =\frac{x}{10}

    ---------------------------------
    Composition of 2nd powder has

    Amount of B1 = \frac{15\times y}{100} = \frac{3y}{20}

    Amount of B2 = \frac{20\times y}{100} = \frac{y}{5}

    ----------------------------------------------

    Total composition of B1 and B2 are equated to the given amount of each

    <br />
 \frac{x}{5} + \frac{3y}{20} = 130

    <br />
\frac{x}{10} + \frac{y}{5} = 80


    Solve these two equations to get x and y

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