1. ## algebra word problem

A pharmacist has two vitamin-supplement powders. The first powder is 20% vitamin B1 and 10% vitamin B2. The second is 15% vitamin B1 and 20% vitamin B2. How many milligrams of each of the two powders should the pharmacist use to make a mixture that contains 130 mg of vitamin B1 and 80 mg of vitamin B2?

any ideas on how to do this?

2. Originally Posted by GriceldaM

A pharmacist has two vitamin-supplement powders. The first powder is 20% vitamin B1 and 10% vitamin B2. The second is 15% vitamin B1 and 20% vitamin B2. How many milligrams of each of the two powders should the pharmacist use to make a mixture that contains 130 mg of vitamin B1 and 80 mg of vitamin B2?

any ideas on how to do this?
Hello GriceldaM
Let x & y be the quantity of first and second powder respectively.
First powder =0.2x (vit B1), 0.1x (vit B2)
second powder =0.15y (vit B1), 0.2y (vit B2)
Vit B1: $0.2x+0.15y=130$
Vit B2: $0.1x+0.2y=80$
Solve to get the values of x & y.

3. Originally Posted by GriceldaM

A pharmacist has two vitamin-supplement powders. The first powder is 20% vitamin B1 and 10% vitamin B2. The second is 15% vitamin B1 and 20% vitamin B2. How many milligrams of each of the two powders should the pharmacist use to make a mixture that contains 130 mg of vitamin B1 and 80 mg of vitamin B2?

any ideas on how to do this?

Lets say he took x milligrams of 1st and y mg of 2nd

-------------------------------------
So composition of 1st powder has

Amount of B1 $= \frac{20 \times x}{100} = \frac{x}{5}$

Amount of B2 $= \frac{10 \times x}{100} =\frac{x}{10}$

---------------------------------
Composition of 2nd powder has

Amount of B1 $= \frac{15\times y}{100} = \frac{3y}{20}$

Amount of B2 $= \frac{20\times y}{100} = \frac{y}{5}$

----------------------------------------------

Total composition of B1 and B2 are equated to the given amount of each

$
\frac{x}{5} + \frac{3y}{20} = 130$

$
\frac{x}{10} + \frac{y}{5} = 80$

Solve these two equations to get x and y