I have an test tomorrow. I studied everything..but i know my teacher will give us hard questions he did not even solve in the class..

how to factor this polynomial:

4y^2 - 81

i know that a^2 - b^2 = (a-b) (a+b)

Simplify:

(m^2 n ^3)^-2 (m^-3 n^2)^-3

we learned that if we have (m^2 m^3)^2 then the answer is m^2 n^3 x m^2 n^3 but how about if we have a -ve square or -3?

Simplify a radical:

√8 + √18

according to my teacher the solution is..

= √(2x2x2) + √(3x3x3)

=2√2 + 3√2

=5√3

how is that possible?

Please help

Thanks in advance