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Math Help - determining the largest set D of real numbers

  1. #1
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    determining the largest set D of real numbers

    hi guys i got another example here which im not to confident with..

    f : D -> R
    <br />
h(x) = \frac{1}{\sqrt{x}-6}+1

    im thinking this would have a slightly different approach because not the whole thing is getting squared.
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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by jvignacio View Post
    hi guys i got another example here which im not to confident with..

    f : D -> R
    <br />
h(x) = \frac{1}{\sqrt{x}-6}+1

    im thinking this would have a slightly different approach because not the whole thing is getting squared.
    Since denominator can't be zero x is not equal to 36

    Since negative inside square root is not allowed

    x (>=) 0

    these are the only two conditions
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  3. #3
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    Quote Originally Posted by ADARSH View Post
    Since denominator can't be zero x is not equal to 36

    Since negative inside square root is not allowed

    x (>=) 0

    these are the only two conditions
    yes yes thats right. so x has to be greater than 0 because u cant square a negative number and if x was 36, then 6-6 = 0 and u cant divide by a 0. UNDERSTOOD

    x >=0 and x not equal to 36
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