Thread: determining the largest set D of real numbers

hi guys i got another example here which im not to confident with..

f : D -> R


im thinking this would have a slightly different approach because not the whole thing is getting squared.

Originally Posted by jvignacio

hi guys i got another example here which im not to confident with..

f : D -> R


im thinking this would have a slightly different approach because not the whole thing is getting squared.

Since denominator can't be zero x is not equal to 36

Since negative inside square root is not allowed

x (>=) 0

these are the only two conditions

Originally Posted by ADARSH

Since denominator can't be zero x is not equal to 36

Since negative inside square root is not allowed

x (>=) 0

these are the only two conditions

yes yes thats right. so x has to be greater than 0 because u cant square a negative number and if x was 36, then 6-6 = 0 and u cant divide by a 0. UNDERSTOOD

x >=0 and x not equal to 36