and the other one using laws of Logs log((10^x)/(x(x^2+6)(x^4+4)))
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Originally Posted by tmac11522 and the other one using laws of Logs log((10^x)/(x(x^2+6)(x^4+4))) $\displaystyle \log_4{11} + 3\log_4{3} = \log_4{11} + \log_4{3^3}$ $\displaystyle = \log_4{11} + \log_4{27}$ $\displaystyle = \log_4{(11 \times 27)}$ $\displaystyle = \log_4{297}$.
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