1. ## can anyone solve...2(2x-4)=9-2(x+1)

can anyone solve...2(2x-4)=9-2(x+1)

I keep gettin different answers...can someone show me what im doing wrong? My finals are tommorow!

2. $\displaystyle 2(2x-4)=9-2(x+1)$
First step is to multiply out both sides to give
$\displaystyle 4x-4=9-2x-2$
Now get all the $\displaystyle x$ terms on one side and all the non $\displaystyle x$ terms on the other, so in this case add 4 to both sides (this will remove the non $\displaystyle x$ term from the left) and add $\displaystyle 2x$ to both sides (this will remove the x term from the right) leaving
$\displaystyle 4x+2x=9-2+4$
Cleaning this up gives
$\displaystyle 6x=11$
and finally divide by 6
$\displaystyle x=\frac{11}{6}$
Hopefully this is one of the answers you got.
Good luck!

3. Originally Posted by pfarnall
$\displaystyle 2(2x-4)=9-2(x+1)$
First step is to multiply out both sides to give
$\displaystyle 4x-4=9-2x-2$
Now get all the $\displaystyle x$ terms on one side and all the non $\displaystyle x$ terms on the other, so in this case add 4 to both sides (this will remove the non $\displaystyle x$ term from the left) and add $\displaystyle 2x$ to both sides (this will remove the x term from the right) leaving
$\displaystyle 4x+2x=9-2+4$
Cleaning this up gives
$\displaystyle 6x=11$
and finally divide by 6
$\displaystyle x=\frac{11}{6}$
Hopefully this is one of the answers you got.
Good luck!
2(2x-4) is not 4x - 4 (little error in first step)

4. ## 4X-8=9-2x*1?

2(2x-4)=9-2(x+1) distribute

2x2=4...2x-4=-8 so lt side is 4X-8
distribute rt side 2 * X=2X...2x1=1 so rt side is 9-2x*1

so far ? 4X-8=9-2x*1

5. ## Thanks for the help!!!

Thanks guys, youre all great!!! I have my finals tommorrow and i am a little worried. Thanks for the help...

6. $\displaystyle 2(2x-4) = 9-2(x+1)$

Remember BEDMAS
First Brackets

$\displaystyle 4x-8 = 9-2x-2$

Now simplify

$\displaystyle 4x-8 = 7-2x$

Now get all the terms with x on one side.

$\displaystyle 4x+2x = 7+8$

Collect like terms.

$\displaystyle 6x = 15$

Divide both sides by 6 to isolate x.

$\displaystyle x = \frac{15}{6}$

Now simplify the fraction to lowest terms.

$\displaystyle x =\frac{5}{2}$

7. Originally Posted by josh_amsterdam
2(2x-4) is not 4x - 4 (little error in first step)
Apologies ... one of those days!

8. ## Someone has to be wrong...

Miller how did you get 15/6...

I got 11/6 as did a few other people... Can someone tell me which one is right?

9. Originally Posted by pfarnall
$\displaystyle 2(2x-4)=9-2(x+1)$
First step is to multiply out both sides to give
$\displaystyle 4x-4=9-2x-2$ (forgot to distribute the two into the -4 on the left side)
Now get all the $\displaystyle x$ terms on one side and all the non $\displaystyle x$ terms on the other, so in this case add 4 to both sides (this will remove the non $\displaystyle x$ term from the left) and add $\displaystyle 2x$ to both sides (this will remove the x term from the right) leaving
$\displaystyle 4x+2x=9-2+4$ (should be 9-2+8)
Cleaning this up gives
$\displaystyle 6x=11$ (6x=15)
and finally divide by 6
$\displaystyle x=\frac{11}{6}$ (should be $\displaystyle x = \frac{15}{6}$, which simplifies down to $\displaystyle \frac{5}{2}$)
Hopefully this is one of the answers you got.
Good luck!
Fixed.

10. millerst is right... x = 15/6 = 5/2