I know that the Eulers relation: 2 cos x = e^ ix + e^-ix 2i sin x = e^ix - e^-ix I was just wondering how i can change 1. 4i*e^x(e^2ix-e^-2ix) 2. 4i*e^x[(-1/2*e^2ix+1/2e^-2ix+ i *(1/2*e^2ix+1/2e^-2ix)] in Eulers relation Thanks
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Hello, Originally Posted by 1234567 I know that the Eulers relation: 2 cos x = e^ ix + e^-ix 2i sin x = e^ix - e^-ix I was just wondering how i can change 1. 4i*e^x(e^2ix-e^-2ix) 2. 4i*e^x[(-1/2*e^2ix+1/2e^-2ix+ i *(1/2*e^2ix+1/2e^-2ix)] in Eulers relation Thanks is it ? you can see that and so we have :
Thank you that helped alot!!
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