# Thread: linear equation in two variables

1. ## linear equation in two variables

solve for x and y

(x+y-8)/2 = (x-2y-14)/3 = (3x+y-12)/11

That's the question, no questions asked!

2. Originally Posted by ice_syncer
solve for x and y

(x+y-8)/2 = (x-2y-14)/3 = (3x+y-12)/11

That's the question, no questions asked!

$\frac{x+y-8}{2}=\frac{x-2y-14}{3}$ . Simplify :

$x+7y+4=0$ ---- 1

$\frac{3x+y-12}{11}=\frac{x+y-8}{2}$ . SImplify :

$5x+9y-64=0$ ---- 2

1x5 $5x+35y+20=0$ ---- 3

3-2 .. carry on here .

$\frac{x+y-8}{2}=\frac{x-2y-14}{3}$ . Simplify :

$x+7y+4=0$ ---- 1

$\frac{3x+y-12}{11}=\frac{x+y-8}{2}$ . SImplify :

$5x+9y-64=0$ ---- 2

1x5 $5x+35y+20=0$ ---- 3

3-2 .. carry on here .
I did the same thing, but the book here said that the answer is x=2, y=6

4. Originally Posted by ice_syncer
I did the same thing, but the book here said that the answer is x=2, y=6

Lets give it a test then :

$\frac{x+y-8}{2}=\frac{x-2y-14}{3}$ , sub x=2 and y=6

$0\neq-8$

so the answers are wrong .

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