If 85a+12b+3c = 47355.87 and
a+b+c = 2035.61 and
a<b<c
What are a,b and c?
$\displaystyle 85a = 47355.87 - 12b-3c$
a $\displaystyle =\frac{47355.87 - 12b-3c}{85}$
......Put this in second equation
$\displaystyle \frac{47355.87 - 12b-3c}{85} + b+ c= 2035.61$
-Get b in terms of c
-Now get a also in terms of c
-Put any value of c and then get value of c and a according to third condition