X^2-5x-3=0? I honestly have no idea how to do this, perhaps x^2-5x=3, but then I'm still stuck, help!
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Originally Posted by fattydq X^2-5x-3=0? I honestly have no idea how to do this, perhaps x^2-5x=3, but then I'm still stuck, help! It doesn't factorise easily, do you know the quadratic formula? So in this case a=1 b=-5 and c=-3
leave the equation equal to 0 to solve. since it can't be factorized you can solve either by where a, b, c are the coefficients of the terms, or you can solve using 'completing the square'
Originally Posted by JeWiSh It doesn't factorise easily, do you know the quadratic formula? So in this case a=1 b=-5 and c=-3 Oh yeah, I did already know that but for some reason my mind just blanked when I saw it. Thanks a bunch!
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