X^2-5x-3=0?
I honestly have no idea how to do this, perhaps x^2-5x=3, but then I'm still stuck, help!
leave the equation equal to 0 to solve.
since it can't be factorized you can solve either by
$\displaystyle \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
where a, b, c are the coefficients of the terms, or you can solve using 'completing the square'
$\displaystyle (x - \frac{5}{2})^2 - \frac{25}{4} - 3$
$\displaystyle (x - \frac{5}{2})^2 = \frac{37}{4}$
$\displaystyle x = \frac{5}{2} \pm \sqrt{\frac{37}{4}}$