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Math Help - solving equation

  1. #1
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    solving equation

    solve the equation 6x^3-19x^2+11x+6=0 so far i got (x-2) as a factor thats as far as i can seem to get
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  2. #2
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    Hi

    You are right !

    So you can factor 6x^3-19x^2+11x+6=0 by x-2 which will give a second degree polynomial
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  3. #3
    A riddle wrapped in an enigma
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    Quote Originally Posted by william View Post
    solve the equation 6x^3-19x^2+11x+6=0 so far i got (x-2) as a factor thats as far as i can seem to get
    Hi william,

    When you divide 6x^3-19x^2+11x+6=0 by x-2, you get 6x^2-7x-3 which should be easily solved using the quadratic formula. The quadratic can be factored as well.
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  4. #4
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    Quote Originally Posted by masters View Post
    Hi william,

    When you divide 6x^3-19x^2+11x+6=0 by x-2, you get 6x^2-7x-3 which should be easily solved using the quadratic formula. The quadratic can be factored as well.
    i got 1.5 and -0.3 is that correct?
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  5. #5
    A riddle wrapped in an enigma
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    Quote Originally Posted by william View Post
    i got 1.5 and -0.3 is that correct?
    Actually, when you solve by factoring 6x^2-7x-3=0, you get:

    (3x+1)(2x-3)=0

    So, the roots are:

    x=-\frac{1}{3} and x=\frac{3}{2}.

    So, one of your roots was correct. You don't want to round off the other one to -.3

    Leave it as a fraction.
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