I think you are still in doubt , isn't it , I saw you peeking at this again and again
---Now if
the denominator on LHS is positive
Hence
but in the initial condition we have taken it greater than 6
Hence this is correct for
---Now when
the denominator on LHS is negative
So there will be a change in inequality sign when we will multiply it by
(x-6) on both sides
Hence
but this is against initial condtion hence no answer in this range of x
----When
the
denominator on LHS is negative
So on multiplying the sign of inequality changes
Hence
thus
is an answer
Now for the complete answer we have to take a combination of all these solution sets(answer as in my last post)
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I am not sure if you were unclear about it, but I think if you were this will be helpful ,ask incase if you still find any trouble
(remember the change of inequality sign on multiplying with a negative number on both sides)