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Math Help - X variable on both side- need help pls!

  1. #1
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    Question X variable on both side- need help pls!

    OK...
    New to this forum....
    I'm a CAD geek by nature & would think Algebra would be a snap...
    But it ain't as I remember it...

    So here's my problem...
    Please provide the step by step solutions... so I can learn this... please...
    Thanks in advance....

    Problem:
    (x-5)/3 -3/2=(4x+7)/6

    Soultion:
    ?????
    Last edited by ThePerfectHacker; November 22nd 2006 at 07:40 PM.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by architech View Post
    OK...
    New to this forum....
    I'm a CAD geek by nature & would think Algebra would be a snap...
    But it ain't as I remember it...

    So here's my problem...
    Please provide the step by step solutions... so I can learn this... please...
    Thanks in advance....

    Problem:
    (x-5)/3 -3/2=(4x+7)/6

    Soultion:
    ?????
    <br />
(x-5)/3 -3/2=(4x+7)/6<br />

    Expand all the brackets:

    <br />
x/3 -5/3-3/2=x/3-19/6=2x/3 + 7/6<br />

    Subtract x/3 from both sides:

    <br />
x/3 - 19/6 -x/3=-19/6 = 2x/3 +7/6 -x/3=x/3+7/6<br />

    or:

    <br />
-19/6=x/3+7/6<br />

    subtract 7/6 form both sides:

    x/3=-13/3

    Multiply by 3:

    x=-13

    RonL
    Last edited by ThePerfectHacker; November 22nd 2006 at 07:41 PM.
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  3. #3
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    Hello, architech!

    Welcome aboard!


    \frac{x-5}{3} -\frac{3}{2}\;=\;\frac{4x+7}{6}

    With an equation, we can eliminate the fractions immediately . . .


    Multiply both sides by the LCD, 6:

    . . . . . . . 6\left(\frac{x-5}{3} - \frac{3}{2}\right) \;= \;6\left(\frac{4x+7}{6}\right)

    . \not{6}^{^2}\left(\frac{x-5}{\not{3}}\right) - \not{6}^{^3}\left(\frac{3}{\not{2}}\right) \;= \;\not{6}\left(\frac{4x+7}{\not{6}}\right)

    . . . . . . . 2(x - 5) - 3(3) \;= \;4x+7

    . . . . . . . . . 2x - 10 - 9 \;=\;4x+7

    . . . . . . . . . . . . . -2x \;= \;26

    . . . . . . . . . . . . . . . \boxed{x \;= \;-13}

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    Talking

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