(3 + x)/(sqrt{3 + x}) = 1 I found x to be -2. The book tells me that the answer is x = -1. How can this be?
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Your answer is correct. Just substitue the value of x in LHS of equation and see it yourself
Originally Posted by arpitagarwal82 Your answer is correct. Just substitue the value of x in LHS of equation and see it yourself I knew that I was right. I find that math books have a lot of wrongs answers in the answer section.
Originally Posted by magentarita (3 + x)/(sqrt{3 + x}) = 1 ]I found x to be -2. The book tells me that the answer is x = -1. How can this be? square both sides: therefore both -3 and -2 are solutions
Originally Posted by e^(i*pi) square both sides: therefore both -3 and -2 are solutions If you plug -3 back into the original equation , you have which is impossible, since is an indeterminate value... XD So magentarita's answer x=-2 is the only solution.
The only answer that makes sense is x = -2. If we replace x with -3, we create division by zero, which is undefined.
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