# Math Help - Binomial expansion questions

1. ## Binomial expansion questions

I think I did this well but I'd like them checked so I know I have the right answers. Could you please look at these for me?

1] $(1 + 2x)^6$
= $1 + 12x + 60x^2 + 160x^3 + 240x^4 + 96x^5 + 64x^6$

2] $(3 + 2x)^5$
= $243 + 810x + 1080x^2 + 730x^3 + 240x^4 + 32x^5$

3] $(5 + 3x)^3$
= $125 + 225x + 135x^2 + 27x^3$

4] $(4 - 2x)^4$
= $256 - 512x + 384x^2 - 108x^3 + 16x^4$

Thanks if you can help with this!

2. Originally Posted by db5vry
I think I did this well but I'd like them checked so I know I have the right answers. Could you please look at these for me?

1] $(1 + 2x)^6$
= $1 + 12x + 60x^2 + 160x^3 + 240x^4 + 96x^5 + 64x^6$

2] $(3 + 2x)^5$
= $243 + 810x + 1080x^2 + 730x^3 + 240x^4 + 32x^5$

3] $(5 + 3x)^3$
= $125 + 225x + 135x^2 + 27x^3$

4] $(4 - 2x)^4$
= $256 - 512x + 384x^2 - 108x^3 + 16x^4$

Thanks if you can help with this!
1, 2, 4 are not correct.

3. Originally Posted by niranjan
1, 2, 4 are not correct.
Okay I made a mistake with a coefficient in the first one - I saw that and corrected it, but I worked out 2 and 4 again:

2] $(3 + 2x)^5$
= $125 + 10x + 40x^2 + 80x^3 + 80x^4 + 32x^5$

4] $(4 - 2x)^4$
= $256 - 8x + 24x^2 - 48x^3 + 16x^4$

Are these right now?

4. Originally Posted by db5vry
Okay I made a mistake with a coefficient in the first one - I saw that and corrected it, but I worked out 2 and 4 again:

2] $(3 + 2x)^5$
= $125 + 10x + 40x^2 + 80x^3 + 80x^4 + 32x^5$

4] $(4 - 2x)^4$
= $256 - 8x + 24x^2 - 48x^3 + 16x^4$

Are these right now?
2] $(3 + 2x)^5$
= $243 + 810x + 1080x^2 + 720x^3 + 240x^4 + 32x^5$

4] $(4 - 2x)^4$
= $256 - 512x + 384x^2 - 128x^3 + 16x^4$