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Math Help - inequality

  1. #1
    Newbie
    Joined
    Aug 2008
    Posts
    21

    inequality

    if abc=1 then demonstrate:
    \frac{a}{b} + \frac{b}{c} + \frac{1}{a} \ge a + b + 1
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  2. #2
    Junior Member
    Joined
    Sep 2007
    Posts
    30
    This should help:
    <br />
\frac{ac}{ac} \frac{a}{b} + \frac{ab}{ab} \frac{b}{c} + \frac{bc}{bc}\frac{1}{a} = <br />
\frac{a^2c}{abc} + \frac{b^2a}{abc} + \frac{bc}{abc} = \frac{a^2c}{1} + \frac{b^2a}{1} + \frac{bc}{1}<br />
= a^2 c + b^2 a + bc<br />
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