1. ## Simple Binomial Expansion

This is a two part question: First it asks to expand $(a + b)^5$, and then to find the coefficient of $x^3$ in the expansion of $(1/4 + 2x)^5$.

I know for part one, you get $a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5$, and that somehow the values of the following are substituted in this answer, but I am not really sure on how this is done or written. Could someone please help in this?

2. Originally Posted by db5vry
This is a two part question: First it asks to expand $(a + b)^5$, and then to find the coefficient of $x^3$ in the expansion of $(1/4 + 2x)^5$.

I know for part one, you get $a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5$, and that somehow the values of the following are substituted in this answer, but I am not really sure on how this is done or written. Could someone please help in this?
Well in the second expansion $a=\frac{1}{4}$ and $b=2x$

So, the coefficient of [/tex]x^3[/tex] is the $10a^2b^3$ part of the expansion, just replace a and b with the values you have.

3. You what the term $10a^2 b^3$ where $a = \frac{1}{4}\;\& \;b = 2x$.

4. Originally Posted by Plato
You what the term $10a^2 b^3$ where $a = \frac{1}{4}\;\& \;b = 2x$.
So it is written as $10(1/4)^2(2x)^3$, which is

$10 x 1/16 x 8$
Which is also 10 multiplied by 0.5
Which is 5
Making the answer $5x^3$?

5. Originally Posted by db5vry
So it is written as $10(1/4)^2(2x)^3$, which is

$10 x 1/16 x 8$
Which is also 10 multiplied by 0.5
Which is 5
Making the answer $5x^3$?

6. Originally Posted by db5vry
So it is written as $10(1/4)^2(2x)^3$, which is

$10 x 1/16 x 8$
Which is also 10 multiplied by 0.5
Which is 5
Making the answer $5x^3$?
Mis-use of Latex - That one line was 10 x 1/16 x 8.
Have I got the right answer?