Hi,
Can anyone help me to solve the following:
I have to express log[base 10]48 in terms of x, y and z . Given that
log[10]24= x , log[10]80=y and log[10]25 = z
Best Regards,
Ananya
Hi Ananya
$\displaystyle log_{10}48 $
$\displaystyle
= log_{10}(24 \times 2)
$
$\displaystyle =log_{10}(24)+log_{10}(2)$
$\displaystyle =log_{10}{(24)+log_{10}(\frac{2^4\times 5}{25^{1/2}})}^{1/4}$
$\displaystyle
=x+log_{10}{(\frac{2^4\times 5}{25^{1/2}})}^{1/4}$
$\displaystyle
=x+\frac{log_{10}(\frac{2^4\times 5}{25^{1/2}})}{4}$
$\displaystyle
=x+\frac{ log_{10} {(2^4\times 5)} - log_{10} 25^{1/2} }{4}$
$\displaystyle
=x+\frac{log_{10}{(80)}-z/2}{4}$
$\displaystyle
=x+\frac{y-z/2}{4}$
GO ahead
Hi Adarsh,
Thanks for the solution .
I have found out another way :
log[base 10] 48
=log[base 10] {(24*80*25)/1000}
= log[10] 24 + log[10] 80 + log[10] 25 - log[10] 1000
= x + y + z - 3
Pardon me for posting the same post twice ...i was getting restless and i thought that thread with the same heading can have related posts.
Best Regards,
Ananya