Hi,

Can anyone help me to solve the following:

I have to express log[base 10]48 in terms of x, y and z . Given that

log[10]24= x , log[10]80=y and log[10]25 = z

Best Regards,

Ananya

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- Mar 7th 2009, 10:13 AMAnanyaLogarithm questions
Hi,

Can anyone help me to solve the following:

I have to express log[base 10]48 in terms of x, y and z . Given that

log[10]24= x , log[10]80=y and log[10]25 = z

Best Regards,

Ananya - Mar 7th 2009, 10:17 AMJhevon
- Mar 7th 2009, 10:23 AMAnanya
Hi,

Can anyone help me to solve the following:

I have to express log[base 10]48 in terms of x, y and z . Given that

log[10]24= x , log[10]80=y and log[10]25 = z

Best Regards,

Ananya - Mar 8th 2009, 01:12 AMADARSH
- Mar 9th 2009, 02:42 AMAnanya
Hi Adarsh,

Thanks for the solution (Yes) .

I have found out another way (Cool) :

log[base 10] 48

=log[base 10] {(24*80*25)/1000}

= log[10] 24 + log[10] 80 + log[10] 25 - log[10] 1000

= x + y + z - 3

Pardon me for posting the same post twice (Blush) ...i was getting restless and i thought that thread with the same heading can have related posts.

Best Regards,

Ananya