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Math Help - Model the problem with a linear equation

  1. #1
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    Model the problem with a linear equation

    Hello everyone. I have spent a long time trying to figure this problem out. I have an exam soon and I am at the stage of anxiety because I cannot move forward studying because I am still not understanding what appears to be a simple problem here. I think that the "where x=0" part is really throwing me off. Any help would be greatly appreciated! thank you.

    Problem:
    Model the problem with a linear equation
    An investment is worth $2958 in 1995. By 2000 it has grown to $5628. Let y be the value of the investment in the year x, where x = 0 represents 1995. Write a linear equation that models the value of the investment in the year x.
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    Quote Originally Posted by lanipr View Post
    Hello everyone. I have spent a long time trying to figure this problem out. I have an exam soon and I am at the stage of anxiety because I cannot move forward studying because I am still not understanding what appears to be a simple problem here. I think that the "where x=0" part is really throwing me off. Any help would be greatly appreciated! thank you.

    Problem:
    Model the problem with a linear equation
    An investment is worth $2958 in 1995. By 2000 it has grown to $5628. Let y be the value of the investment in the year x, where x = 0 represents 1995. Write a linear equation that models the value of the investment in the year x.
    A linear equation is of the form y = mx + c, where m is the slope and c is the y-intercept. Note, the y-intercept is given, it's 2958. So all you need is the slope.

    It's found by m = \frac{y_2 - y_1}{x_2 - x_1}

     = \frac{5628 - 2958}{5 - 0} (the second x value must be 5, because it's 5 years on...)

     = \frac{2670}{5}

     = 534.


    So the equation of the line is y = 534x + 2958.
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