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Math Help - Linear Equation Q3

  1. #1
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    Linear Equation Q3

    Question
     \frac{3x^2+4}{x^3+8}=\frac{3}{x+2}

    Attempt:

     3x^3+6x^2+4x+8=3x^3+24

    Final answer I got is 2


    Please check my answer because i think it is wrong

    Thank you
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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    Quote Originally Posted by mj.alawami View Post
    Question
     \frac{3x^2+4}{x^3+8}=\frac{3}{x+2}

    Attempt:

     3x^3+6x^2+4x+8=3x^3+24

    Final answer I got is 2


    Please check my answer because i think it is wrong

    Thank you
     3x^3+6x^2+4x+8=3x^3+24
    6x^2 +4x-16=0

    3x^2 + 2x-8=0<br />

    3x^2 + 6x-4x-8=0

    3x(x+2)-4(x+2)=0

    (3x-4)(x+2)=0

    x=4/3 or x=(-2)


    But -2 is not allowed as denominator can't be 0
    Last edited by ADARSH; March 9th 2009 at 09:07 AM. Reason: left last line
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