Sketch the following curves : (1) y^2=x(1-x^2) Not sure how to do this when y is squared . Thanks .
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Originally Posted by thereddevils Sketch the following curves : (1) y^2=x(1-x^2) Not sure how to do this when y is squared . Thanks . If you multiply the x bit out you can then square root both sides, to get
Yes, you can do that but remember that y can be negative also: .
Originally Posted by HallsofIvy Yes, you can do that but remember that y can be negative also: . Yes i know i can do that . But i am unsure of how to find the horizontal and vertical asymtotes and other informations to sketch .
What makes you think there are any asymptotes? You should do simple things like finding the x and y intercepts and turning points if there are any.
Exactly , i am confusing myself . Well , let me try here When y=0 ,x=0,1,-1 When i differentiate to find the turning points , i am stucked here . Equate it to 0 , i got , isn't it the same when i put y=0 and solve for x earlier .
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