# [SOLVED] How to factor these two dudes...

• March 4th 2009, 04:28 PM
p00ndawg
[SOLVED] How to factor these two dudes...
4r^2 - 4r -3

9r^2 + 6r + 82

Im embarrassed to say I could not factor these for repeated roots.

Lern me right plz.
• March 4th 2009, 06:39 PM
skeeter
Quote:

Originally Posted by p00ndawg
4r^2 - 4r -3

9r^2 + 6r + 82

Im embarrassed to say I could not factor these for repeated roots.

Lern me right plz.

$4r^2 - 4r - 3 = (2r - 3)(2r + 1)$

the second quadratic will not factor over the reals, but ...

$(9r^2 + 6r + 1) + 81$

$(3r+1)^2 - (-81)$

$[(3r+1) - 9i] \cdot [(3r+1) + 9i]$